What are the solutions to the equation -x^2+72x=-216-7x^2 ?

The solutions to the equation -x^2+72x=-216-7x^2 are x=-6

Find the zeros of -x^2+72x=-216-7x^2

The zeros of -x^2+72x=-216-7x^2 are x=-6

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- x^{2} + 72 x = - 216 - 7 x^{2}

x = - 6

Solution steps

- x^{2} + 72 x = - 216 - 7 x^{2}

Move

7 x^{2}

to the left side

6 x^{2} + 72 x = - 216

Move

216

to the left side

6 x^{2} + 72 x + 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 6 \cdot 216}{2 \cdot 6}

7 2^{2} - 4 \cdot 6 \cdot 216 = 0

x_{1, 2} = \frac{- 72 \pm 0}{2 \cdot 6}

x = \frac{- 72}{2 \cdot 6}

\frac{- 72}{2 \cdot 6} = - 6

x = - 6

The solution to the quadratic equation is:

x = - 6

- 5 x^{2} + x + 4 = 0

n^{2} + 7 n + 6 = 0

x (x + 1) = 5 x - 4

7 x - x^{2} = 0

12 x - 5 = - 4 x^{2}

What are the solutions to the equation -x^2+72x=-216-7x^2 ?
The solutions to the equation -x^2+72x=-216-7x^2 are x=-6
Find the zeros of -x^2+72x=-216-7x^2
The zeros of -x^2+72x=-216-7x^2 are x=-6