What are the solutions to the equation 100x^2+20x+1=0 ?

The solutions to the equation 100x^2+20x+1=0 are x=-1/10

Find the zeros of 100x^2+20x+1=0

The zeros of 100x^2+20x+1=0 are x=-1/10

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100 x^{2} + 20 x + 1 = 0

x = - \frac{1}{10}

Decimal Notation

x = - 0.1

Solution steps

100 x^{2} + 20 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 100 \cdot 1}{2 \cdot 100}

2 0^{2} - 4 \cdot 100 \cdot 1 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 100}

x = \frac{- 20}{2 \cdot 100}

\frac{- 20}{2 \cdot 100} = - \frac{1}{10}

x = - \frac{1}{10}

The solution to the quadratic equation is:

x = - \frac{1}{10}

5 x^{2} - 27 x - 18 = 0

x^{2} + (x + 14)^{2} = 3 4^{2}

X^{2} + 5 X - 14 = 0

x^{2} - \frac{2}{3} x

(x + 5)^{2} + 16 = 0

What are the solutions to the equation 100x^2+20x+1=0 ?
The solutions to the equation 100x^2+20x+1=0 are x=-1/10
Find the zeros of 100x^2+20x+1=0
The zeros of 100x^2+20x+1=0 are x=-1/10