What are the solutions to the equation 0=4x^2-4x+1 ?

The solutions to the equation 0=4x^2-4x+1 are x= 1/2

Find the zeros of 0=4x^2-4x+1

The zeros of 0=4x^2-4x+1 are x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 4 x^{2} - 4 x + 1

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

0 = 4 x^{2} - 4 x + 1

Switch sides

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

\frac{x ^{2}}{5} - \frac{x}{2} = \frac{4}{5}

y^{2} + 1 = \frac{y + 8}{2}

20 x^{2} + 13 x - 15 = 0

3 5^{2} = 6^{2} + x^{2}

f, (f)^{2} + g = x y - 1

What are the solutions to the equation 0=4x^2-4x+1 ?
The solutions to the equation 0=4x^2-4x+1 are x= 1/2
Find the zeros of 0=4x^2-4x+1
The zeros of 0=4x^2-4x+1 are x= 1/2