What are the solutions to the equation x^2+9x^2+20=0 ?

The solutions to the equation x^2+9x^2+20=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^2+9x^2+20=0

The zeros of x^2+9x^2+20=0 are x=sqrt(2)i,x=-sqrt(2)i

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x^{2} + 9 x^{2} + 20 = 0

x = 2 i, x = - 2 i

Solution steps

x^{2} + 9 x^{2} + 20 = 0

Move

20

to the right side

x^{2} + 9 x^{2} = - 20

Add similar elements:

x^{2} + 9 x^{2} = 10 x^{2}

10 x^{2} = - 20

Divide both sides by

10

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

x, x^{2} + 4 x + 9 = 0

x^{2} = \frac{16}{9}

y, x^{4} + x^{3} y = 4 y^{2} x + y

3 x^{2} - 6 x - 144 = 0

2 x^{2} + x = 4

What are the solutions to the equation x^2+9x^2+20=0 ?
The solutions to the equation x^2+9x^2+20=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^2+9x^2+20=0
The zeros of x^2+9x^2+20=0 are x=sqrt(2)i,x=-sqrt(2)i