What are the solutions to the equation -b^2-7=-23 ?

The solutions to the equation -b^2-7=-23 are b=4,b=-4

Find the zeros of -b^2-7=-23

The zeros of -b^2-7=-23 are b=4,b=-4

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- b^{2} - 7 = - 23

b = 4, b = - 4

Solution steps

- b^{2} - 7 = - 23

Move

7

to the right side

- b^{2} = - 16

Divide both sides by

- 1

b^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 16, b = - 16

16 = 4

- 16 = - 4

b = 4, b = - 4

b (b - 5) - 9 = 0

x (x + 6) = 3

2 x^{2} - 1 = x

(x - 1) (2 x - 1) = (x + 1)^{2}

n = x^{2} - 2 x

What are the solutions to the equation -b^2-7=-23 ?
The solutions to the equation -b^2-7=-23 are b=4,b=-4
Find the zeros of -b^2-7=-23
The zeros of -b^2-7=-23 are b=4,b=-4