What is the answer to |x^2-4x|=3 ?

The answer to |x^2-4x|=3 is x=2-sqrt(7)\lor x=1\lor x=3\lor x=2+sqrt(7)

Solve for x: |x^2-4x|=3

The solution is x=2-sqrt(7)\lor x=1\lor x=3\lor x=2+sqrt(7)

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x^{2} - 4 x = 3

x = 2 - 7 or x = 1 or x = 3 or x = 2 + 7

Decimal Notation

x = - 0.64575 \dots, x = 1, x = 3, x = 4.64575 \dots

Solution steps

x^{2} - 4 x = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x = - 3 or x^{2} - 4 x = 3

x^{2} - 4 x = - 3 or x^{2} - 4 x = 3

(x = 1 or x = 3) or (x = 2 - 7 or x = 2 + 7)

x = 2 - 7 or x = 1 or x = 3 or x = 2 + 7

∣ 2 x + 5 ∣ - 1 < 0

2 ∣ 2 x - 1 ∣ - 8 = 18

\frac{8 x ^{7} y}{40 x ^{8} y ^{6}}

- \frac{8}{2}

\frac{u}{- 4} \geq 10

What is the answer to |x^2-4x|=3 ?
The answer to |x^2-4x|=3 is x=2-sqrt(7)\lor x=1\lor x=3\lor x=2+sqrt(7)
Solve for x: |x^2-4x|=3
The solution is x=2-sqrt(7)\lor x=1\lor x=3\lor x=2+sqrt(7)