What are the solutions to the equation solvefor x,x^2+4x+4=0 ?

The solutions to the equation solvefor x,x^2+4x+4=0 are x=-2

Find the zeros of solvefor x,x^2+4x+4=0

The zeros of solvefor x,x^2+4x+4=0 are x=-2

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x, x^{2} + 4 x + 4 = 0

x = - 2

Solution steps

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

x^{2} + 10 x - 10 = 0

2 x^{2} + 10 x = 0

1 1^{2} + 8^{2} = x^{2}

x^{2} - 16 x + 64 = 4

(3 x + 2) (5 x + 1) = a x^{2} + b x + 2

What are the solutions to the equation solvefor x,x^2+4x+4=0 ?
The solutions to the equation solvefor x,x^2+4x+4=0 are x=-2
Find the zeros of solvefor x,x^2+4x+4=0
The zeros of solvefor x,x^2+4x+4=0 are x=-2