What are the solutions to the equation -4x^2+6x-25=0 ?

The solutions to the equation -4x^2+6x-25=0 are x= 3/4-i(sqrt(91))/4 ,x= 3/4+i(sqrt(91))/4

Find the zeros of -4x^2+6x-25=0

The zeros of -4x^2+6x-25=0 are x= 3/4-i(sqrt(91))/4 ,x= 3/4+i(sqrt(91))/4

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- 4 x^{2} + 6 x - 25 = 0

x = \frac{3}{4} - i \frac{91}{4}, x = \frac{3}{4} + i \frac{91}{4}

Solution steps

- 4 x^{2} + 6 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) ( - 25 )}{2 ( - 4 )}

Simplify

6^{2} - 4 (- 4) (- 25) : 291 i

x_{1, 2} = \frac{- 6 \pm 2 91 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 91 i}{2 ( - 4 )}, x_{2} = \frac{- 6 - 2 91 i}{2 ( - 4 )}

x = \frac{- 6 + 2 91 i}{2 ( - 4 )} : \frac{3}{4} - i \frac{91}{4}

x = \frac{- 6 - 2 91 i}{2 ( - 4 )} : \frac{3}{4} + i \frac{91}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{91}{4}, x = \frac{3}{4} + i \frac{91}{4}

5 x^{2} + 4 x - 28 = 0

5^{2} = 4 x^{2} - 4 x + 1 + x^{2}

3 x^{2} - 5 x + 10 = 0

2 x^{2} - 10 x = - 8

5 x^{2} - 5 x - 2 = 0

What are the solutions to the equation -4x^2+6x-25=0 ?
The solutions to the equation -4x^2+6x-25=0 are x= 3/4-i(sqrt(91))/4 ,x= 3/4+i(sqrt(91))/4
Find the zeros of -4x^2+6x-25=0
The zeros of -4x^2+6x-25=0 are x= 3/4-i(sqrt(91))/4 ,x= 3/4+i(sqrt(91))/4