What are the solutions to the equation 2(x-3)^2-32=0 ?

The solutions to the equation 2(x-3)^2-32=0 are x=7,x=-1

Find the zeros of 2(x-3)^2-32=0

The zeros of 2(x-3)^2-32=0 are x=7,x=-1

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2 (x - 3)^{2} - 32 = 0

x = 7, x = - 1

Solution steps

2 (x - 3)^{2} - 32 = 0

Move

32

to the right side

2 (x - 3)^{2} = 32

Divide both sides by

2

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

- 3 x^{2} - 2 x + 12

2 w^{2} + w - 7 = 0

3 x^{2} - 3 x - 10 = 0

4 x^{2} + 5 x + 5 = 0

(x - 3)^{2} + 5 = - 11

What are the solutions to the equation 2(x-3)^2-32=0 ?
The solutions to the equation 2(x-3)^2-32=0 are x=7,x=-1
Find the zeros of 2(x-3)^2-32=0
The zeros of 2(x-3)^2-32=0 are x=7,x=-1