What are the solutions to the equation -5(x+1)(x-3)=0 ?

The solutions to the equation -5(x+1)(x-3)=0 are x=-1,x=3

Find the zeros of -5(x+1)(x-3)=0

The zeros of -5(x+1)(x-3)=0 are x=-1,x=3

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- 5 (x + 1) (x - 3) = 0

x = - 1, x = 3

Solution steps

- 5 (x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 1, x = 3

y, 2 x y - y^{2} = 1

r^{2} + 4 r - 1 = 0

6 v^{2} - 30 v = 0

x^{2} - 6 x + 135 = 0

(x + 2)^{2} - (x - 2)^{2} = x^{2} + 7

What are the solutions to the equation -5(x+1)(x-3)=0 ?
The solutions to the equation -5(x+1)(x-3)=0 are x=-1,x=3
Find the zeros of -5(x+1)(x-3)=0
The zeros of -5(x+1)(x-3)=0 are x=-1,x=3