What are the solutions to the equation (x+3)(x+4)=6 ?

The solutions to the equation (x+3)(x+4)=6 are x=-1,x=-6

Find the zeros of (x+3)(x+4)=6

The zeros of (x+3)(x+4)=6 are x=-1,x=-6

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(x + 3) (x + 4) = 6

x = - 1, x = - 6

Solution steps

(x + 3) (x + 4) = 6

Expand

(x + 3) (x + 4) : x^{2} + 7 x + 12

x^{2} + 7 x + 12 = 6

Move

6

to the left side

x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 1}, x_{2} = \frac{- 7 - 5}{2 \cdot 1}

x = \frac{- 7 + 5}{2 \cdot 1} : - 1

x = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

r, a = 2 π r^{2} + 2 π r h

p, x^{2} - (2 p - 1) x + p^{2} - p - 6 = 0

x^{2} - 1.4 x + 0.45 = 0

(x + 1)^{2} - 2 = 0

x^{2} - 12 x - 5 = 0

What are the solutions to the equation (x+3)(x+4)=6 ?
The solutions to the equation (x+3)(x+4)=6 are x=-1,x=-6
Find the zeros of (x+3)(x+4)=6
The zeros of (x+3)(x+4)=6 are x=-1,x=-6