What are the solutions to the equation x^2+20x=-225 ?

The solutions to the equation x^2+20x=-225 are x=-10+5sqrt(5)i,x=-10-5sqrt(5)i

Find the zeros of x^2+20x=-225

The zeros of x^2+20x=-225 are x=-10+5sqrt(5)i,x=-10-5sqrt(5)i

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x^{2} + 20 x = - 225

x = - 10 + 55 i, x = - 10 - 55 i

Solution steps

x^{2} + 20 x = - 225

Move

225

to the left side

x^{2} + 20 x + 225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 225}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 225 : 105 i

x_{1, 2} = \frac{- 20 \pm 10 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 10 5 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 10 5 i}{2 \cdot 1}

x = \frac{- 20 + 10 5 i}{2 \cdot 1} : - 10 + 55 i

x = \frac{- 20 - 10 5 i}{2 \cdot 1} : - 10 - 55 i

The solutions to the quadratic equation are:

x = - 10 + 55 i, x = - 10 - 55 i

9 x + 4 < 2 x + 4

12 x^{3} + 2 x^{2} + 6 x

\frac{1}{3} n \geq 9

5 \cdot 8

5 x - 0.02 + x = 11.98

What are the solutions to the equation x^2+20x=-225 ?
The solutions to the equation x^2+20x=-225 are x=-10+5sqrt(5)i,x=-10-5sqrt(5)i
Find the zeros of x^2+20x=-225
The zeros of x^2+20x=-225 are x=-10+5sqrt(5)i,x=-10-5sqrt(5)i