What are the solutions to the equation x^2+6x=5+3 ?

The solutions to the equation x^2+6x=5+3 are x=-3+sqrt(17),x=-3-sqrt(17)

Find the zeros of x^2+6x=5+3

The zeros of x^2+6x=5+3 are x=-3+sqrt(17),x=-3-sqrt(17)

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x^{2} + 6 x = 5 + 3

x = - 3 + 17, x = - 3 - 17

Decimal Notation

x = 1.12310 \dots, x = - 7.12310 \dots

Solution steps

x^{2} + 6 x = 5 + 3

Refine

x^{2} + 6 x = 8

Move

8

to the left side

x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 8) = 217

x_{1, 2} = \frac{- 6 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 17}{2 \cdot 1}

x = \frac{- 6 + 2 17}{2 \cdot 1} : - 3 + 17

x = \frac{- 6 - 2 17}{2 \cdot 1} : - 3 - 17

The solutions to the quadratic equation are:

x = - 3 + 17, x = - 3 - 17

- x^{2} + 10 x + 2 = 0

7 v = v^{2}

- 8 x^{2} + 12 x = 0

8 x^{2} = 36 x

f, f \cdot g f = 4 x^{3} - x + 2

What are the solutions to the equation x^2+6x=5+3 ?
The solutions to the equation x^2+6x=5+3 are x=-3+sqrt(17),x=-3-sqrt(17)
Find the zeros of x^2+6x=5+3
The zeros of x^2+6x=5+3 are x=-3+sqrt(17),x=-3-sqrt(17)