What are the solutions to the equation 6=(V^2)/(2(20/3)) ?

The solutions to the equation 6=(V^2)/(2(20/3)) are V=4sqrt(5),V=-4sqrt(5)

Find the zeros of 6=(V^2)/(2(20/3))

The zeros of 6=(V^2)/(2(20/3)) are V=4sqrt(5),V=-4sqrt(5)

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6 = \frac{V ^{2}}{2 ( \frac{20}{3} )}

V = 45, V = - 45

Decimal Notation

V = 8.94427 \dots, V = - 8.94427 \dots

Solution steps

6 = \frac{V ^{2}}{2 ( \frac{20}{3} )}

Switch sides

\frac{V ^{2}}{2 ( \frac{20}{3} )} = 6

Multiply both sides by

2 \frac{20}{3}

V^{2} = 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

V = 80, V = - 80

80 = 45

- 80 = - 45

V = 45, V = - 45

x^{2} + 16 x + 4 = 0

2 (m - 1) (1 + m) = m

x, x^{2} + 4 x + 13 = 0

16.4 = 8.1 t + 4.9 t^{2}

480 = (6 x - 4) (4 x - 4) (2)

What are the solutions to the equation 6=(V^2)/(2(20/3)) ?
The solutions to the equation 6=(V^2)/(2(20/3)) are V=4sqrt(5),V=-4sqrt(5)
Find the zeros of 6=(V^2)/(2(20/3))
The zeros of 6=(V^2)/(2(20/3)) are V=4sqrt(5),V=-4sqrt(5)