What are the solutions to the equation t^2-8t=0 ?

The solutions to the equation t^2-8t=0 are t=8,t=0

Find the zeros of t^2-8t=0

The zeros of t^2-8t=0 are t=8,t=0

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t^{2} - 8 t = 0

t = 8, t = 0

Solution steps

t^{2} - 8 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

t_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, t_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

t = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

t = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 8, t = 0

13 - 6 x = (2 x - 5)^{2} + 3

x, - \frac{1}{y} = x - 4 x^{2}

0 = - 4.9 t^{2} + 4.25 t + 100

m^{2} + 17 m + 72 = 0

2 x^{2} - 12 x + 2 = 0

What are the solutions to the equation t^2-8t=0 ?
The solutions to the equation t^2-8t=0 are t=8,t=0
Find the zeros of t^2-8t=0
The zeros of t^2-8t=0 are t=8,t=0