What are the solutions to the equation 0=x^2-2x+4 ?

The solutions to the equation 0=x^2-2x+4 are x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of 0=x^2-2x+4

The zeros of 0=x^2-2x+4 are x=1+sqrt(3)i,x=1-sqrt(3)i

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0 = x^{2} - 2 x + 4

x = 1 + 3 i, x = 1 - 3 i

Solution steps

0 = x^{2} - 2 x + 4

Switch sides

x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

100 x^{2} - 20 x + 1 = 0

3 m^{2} + 2 m + 2 = 0

x^{2} - 5 x + 6 = 21 - 3 x

(a + 1) x^{2} + 4 a x = 8 x - 2 a

2 h^{2} - 38 h + 168 = 0

What are the solutions to the equation 0=x^2-2x+4 ?
The solutions to the equation 0=x^2-2x+4 are x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of 0=x^2-2x+4
The zeros of 0=x^2-2x+4 are x=1+sqrt(3)i,x=1-sqrt(3)i