What are the solutions to the equation x^2-2ax+(a^2+b^2)=0 ?

The solutions to the equation x^2-2ax+(a^2+b^2)=0 are x=a+ib,x=a-ib

Find the zeros of x^2-2ax+(a^2+b^2)=0

The zeros of x^2-2ax+(a^2+b^2)=0 are x=a+ib,x=a-ib

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x^{2} - 2 a x + (a^{2} + b^{2}) = 0

x = a + ib, x = a - ib

Solution steps

x^{2} - 2 a x + (a^{2} + b^{2}) = 0

Refine

x^{2} - 2 a x + a^{2} + b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot ( a ^{2} + b ^{2} )}{2 \cdot 1}

Simplify

(- 2 a)^{2} - 4 \cdot 1 \cdot (a^{2} + b^{2}) : 2 ib

x_{1, 2} = \frac{- ( - 2 a ) \pm 2 ib}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 a ) + 2 ib}{2 \cdot 1}, x_{2} = \frac{- ( - 2 a ) - 2 ib}{2 \cdot 1}

x = \frac{- ( - 2 a ) + 2 ib}{2 \cdot 1} : a + ib

x = \frac{- ( - 2 a ) - 2 ib}{2 \cdot 1} : a - ib

The solutions to the quadratic equation are:

x = a + ib, x = a - ib

x, x^{2} y - 2 x^{2} - y - 2 = 0

63 - 16 x = - x^{2}

0 = 9 x^{2} - 3 x

x^{2} + x + x = 0

(x + 6) (x - 3) = - 8

What are the solutions to the equation x^2-2ax+(a^2+b^2)=0 ?
The solutions to the equation x^2-2ax+(a^2+b^2)=0 are x=a+ib,x=a-ib
Find the zeros of x^2-2ax+(a^2+b^2)=0
The zeros of x^2-2ax+(a^2+b^2)=0 are x=a+ib,x=a-ib