What are the solutions to the equation 18x^2-720x+5400=0 ?

The solutions to the equation 18x^2-720x+5400=0 are x=30,x=10

Find the zeros of 18x^2-720x+5400=0

The zeros of 18x^2-720x+5400=0 are x=30,x=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

18 x^{2} - 720 x + 5400 = 0

x = 30, x = 10

Solution steps

18 x^{2} - 720 x + 5400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 720 ) \pm ( - 720 ) ^{2} - 4 \cdot 18 \cdot 5400}{2 \cdot 18}

(- 720)^{2} - 4 \cdot 18 \cdot 5400 = 360

x_{1, 2} = \frac{- ( - 720 ) \pm 360}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 720 ) + 360}{2 \cdot 18}, x_{2} = \frac{- ( - 720 ) - 360}{2 \cdot 18}

x = \frac{- ( - 720 ) + 360}{2 \cdot 18} : 30

x = \frac{- ( - 720 ) - 360}{2 \cdot 18} : 10

The solutions to the quadratic equation are:

x = 30, x = 10

a, a^{2} + b^{2} = 2 a - 6 b - 10

12 x^{2} - x - 13 = 0

(x + 3)^{2} + 2 (x + 1) = 31

10 = - 5 t^{2}

x, x^{2} + 4 x - 1 = 0

What are the solutions to the equation 18x^2-720x+5400=0 ?
The solutions to the equation 18x^2-720x+5400=0 are x=30,x=10
Find the zeros of 18x^2-720x+5400=0
The zeros of 18x^2-720x+5400=0 are x=30,x=10