What are the solutions to the equation 0=2x^2-16x-18 ?

The solutions to the equation 0=2x^2-16x-18 are x=9,x=-1

Find the zeros of 0=2x^2-16x-18

The zeros of 0=2x^2-16x-18 are x=9,x=-1

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0 = 2 x^{2} - 16 x - 18

x = 9, x = - 1

Solution steps

0 = 2 x^{2} - 16 x - 18

Switch sides

2 x^{2} - 16 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 (- 18) = 20

x_{1, 2} = \frac{- ( - 16 ) \pm 20}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 20}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 20}{2 \cdot 2}

x = \frac{- ( - 16 ) + 20}{2 \cdot 2} : 9

x = \frac{- ( - 16 ) - 20}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

1^{2} + 4^{2} = x^{2}

- 9 r^{2} + 9 r + 6 = 4

q^{2} - 4 q - 45 = 0

x^{3} - 6 x^{2} + 15 x - 7 = (x + a)^{3} + b x + c

0 = - x^{2} + 3 x + 4

What are the solutions to the equation 0=2x^2-16x-18 ?
The solutions to the equation 0=2x^2-16x-18 are x=9,x=-1
Find the zeros of 0=2x^2-16x-18
The zeros of 0=2x^2-16x-18 are x=9,x=-1