What are the solutions to the equation -x^2-2/5 x=1 ?

The solutions to the equation -x^2-2/5 x=1 are x=-1/5-i(2sqrt(6))/5 ,x=-1/5+i(2sqrt(6))/5

Find the zeros of -x^2-2/5 x=1

The zeros of -x^2-2/5 x=1 are x=-1/5-i(2sqrt(6))/5 ,x=-1/5+i(2sqrt(6))/5

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- x^{2} - \frac{2}{5} x = 1

x = - \frac{1}{5} - i \frac{2 6}{5}, x = - \frac{1}{5} + i \frac{2 6}{5}

Solution steps

- x^{2} - \frac{2}{5} x = 1

Multiply both sides by

5

- 5 x^{2} - 2 x = 5

Move

5

to the left side

- 5 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 5 ) ( - 5 )}{2 ( - 5 )}

Simplify

(- 2)^{2} - 4 (- 5) (- 5) : 46 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 6 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 6 i}{2 ( - 5 )}, x_{2} = \frac{- ( - 2 ) - 4 6 i}{2 ( - 5 )}

x = \frac{- ( - 2 ) + 4 6 i}{2 ( - 5 )} : - \frac{1}{5} - i \frac{2 6}{5}

x = \frac{- ( - 2 ) - 4 6 i}{2 ( - 5 )} : - \frac{1}{5} + i \frac{2 6}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} - i \frac{2 6}{5}, x = - \frac{1}{5} + i \frac{2 6}{5}

9 x^{2} - 12 x = - 4

5 x^{2} - 9 x - 18 = 0

- 2 x^{2} + 7 x - 5 = 0

3 x^{2} + 192 = 0

(x + 2)^{2} - (x - 1)^{2} - (x + 3)^{2} = 0

What are the solutions to the equation -x^2-2/5 x=1 ?
The solutions to the equation -x^2-2/5 x=1 are x=-1/5-i(2sqrt(6))/5 ,x=-1/5+i(2sqrt(6))/5
Find the zeros of -x^2-2/5 x=1
The zeros of -x^2-2/5 x=1 are x=-1/5-i(2sqrt(6))/5 ,x=-1/5+i(2sqrt(6))/5