What are the solutions to the equation 2w^2-w=120 ?

The solutions to the equation 2w^2-w=120 are w=8,w=-15/2

Find the zeros of 2w^2-w=120

The zeros of 2w^2-w=120 are w=8,w=-15/2

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2 w^{2} - w = 120

w = 8, w = - \frac{15}{2}

Decimal Notation

w = 8, w = - 7.5

Solution steps

2 w^{2} - w = 120

Move

120

to the left side

2 w^{2} - w - 120 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 120) = 31

w_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 2}, w_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 2}

w = \frac{- ( - 1 ) + 31}{2 \cdot 2} : 8

w = \frac{- ( - 1 ) - 31}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

w = 8, w = - \frac{15}{2}

t^{2} - 125 = 0

y, \frac{d y}{d x} = x^{2} + e^{x} \cdot y^{2}

- 2 x^{2} + 7 x - 8 = 0

x^{2} = - 4 x + 21

x^{2} + 1 = - x^{2} + 9

What are the solutions to the equation 2w^2-w=120 ?
The solutions to the equation 2w^2-w=120 are w=8,w=-15/2
Find the zeros of 2w^2-w=120
The zeros of 2w^2-w=120 are w=8,w=-15/2