What are the solutions to the equation x(x+1)=360 ?

The solutions to the equation x(x+1)=360 are x=(-1+sqrt(1441))/2 ,x=(-1-sqrt(1441))/2

Find the zeros of x(x+1)=360

The zeros of x(x+1)=360 are x=(-1+sqrt(1441))/2 ,x=(-1-sqrt(1441))/2

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x (x + 1) = 360

x = \frac{- 1 + 1441}{2}, x = \frac{- 1 - 1441}{2}

Decimal Notation

x = 18.48025 \dots, x = - 19.48025 \dots

Solution steps

x (x + 1) = 360

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 360

Move

360

to the left side

x^{2} + x - 360 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 360 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 360) = 1441

x_{1, 2} = \frac{- 1 \pm 1441}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1441}{2 \cdot 1}, x_{2} = \frac{- 1 - 1441}{2 \cdot 1}

x = \frac{- 1 + 1441}{2 \cdot 1} : \frac{- 1 + 1441}{2}

x = \frac{- 1 - 1441}{2 \cdot 1} : \frac{- 1 - 1441}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 1441}{2}, x = \frac{- 1 - 1441}{2}

x, x^{2} y + y = x + 1

4 (x + 3)^{2} = 32

t^{2} - 10 t + 9 = 0

8 x^{2} + 6 x = 0

x (x + 2) = 24

What are the solutions to the equation x(x+1)=360 ?
The solutions to the equation x(x+1)=360 are x=(-1+sqrt(1441))/2 ,x=(-1-sqrt(1441))/2
Find the zeros of x(x+1)=360
The zeros of x(x+1)=360 are x=(-1+sqrt(1441))/2 ,x=(-1-sqrt(1441))/2