What are the solutions to the equation -2x^2+12x-9=0 ?

The solutions to the equation -2x^2+12x-9=0 are x=(3(2-sqrt(2)))/2 ,x=(3(2+sqrt(2)))/2

Find the zeros of -2x^2+12x-9=0

The zeros of -2x^2+12x-9=0 are x=(3(2-sqrt(2)))/2 ,x=(3(2+sqrt(2)))/2

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- 2 x^{2} + 12 x - 9 = 0

x = \frac{3 ( 2 - 2 )}{2}, x = \frac{3 ( 2 + 2 )}{2}

Decimal Notation

x = 0.87867 \dots, x = 5.12132 \dots

Solution steps

- 2 x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 9) = 62

x_{1, 2} = \frac{- 12 \pm 6 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 6 2}{2 ( - 2 )}, x_{2} = \frac{- 12 - 6 2}{2 ( - 2 )}

x = \frac{- 12 + 6 2}{2 ( - 2 )} : \frac{3 ( 2 - 2 )}{2}

x = \frac{- 12 - 6 2}{2 ( - 2 )} : \frac{3 ( 2 + 2 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 - 2 )}{2}, x = \frac{3 ( 2 + 2 )}{2}

x^{2} + x^{2} = 1 8^{2}

x (x + 1) = 132

2 v^{2} + 12 = 14 v

(x^{2} - 8) = 0

\frac{1}{2} - y^{2} + 3 = 0

What are the solutions to the equation -2x^2+12x-9=0 ?
The solutions to the equation -2x^2+12x-9=0 are x=(3(2-sqrt(2)))/2 ,x=(3(2+sqrt(2)))/2
Find the zeros of -2x^2+12x-9=0
The zeros of -2x^2+12x-9=0 are x=(3(2-sqrt(2)))/2 ,x=(3(2+sqrt(2)))/2