What are the solutions to the equation 2(x-3)^2=4 ?

The solutions to the equation 2(x-3)^2=4 are x=sqrt(2)+3,x=-sqrt(2)+3

Find the zeros of 2(x-3)^2=4

The zeros of 2(x-3)^2=4 are x=sqrt(2)+3,x=-sqrt(2)+3

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2 (x - 3)^{2} = 4

x = 2 + 3, x = - 2 + 3

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

2 (x - 3)^{2} = 4

Divide both sides by

2

(x - 3)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 2 : x = 2 + 3

Solve

x - 3 = - 2 : x = - 2 + 3

The solutions to the quadratic equation are:

x = 2 + 3, x = - 2 + 3

x^{2} + (x - 2)^{2} = (x + 2)^{2}

\frac{2}{5} y^{2} + \frac{1}{5} y + \frac{3}{5} = 0

(x + 7) (x - 9) = 0

X^{2} = 2 + X

s (s + 2) = 0

What are the solutions to the equation 2(x-3)^2=4 ?
The solutions to the equation 2(x-3)^2=4 are x=sqrt(2)+3,x=-sqrt(2)+3
Find the zeros of 2(x-3)^2=4
The zeros of 2(x-3)^2=4 are x=sqrt(2)+3,x=-sqrt(2)+3