What are the solutions to the equation completesquare x^2+12x-4 ?

The solutions to the equation completesquare x^2+12x-4 are (x+6)^2-40

Find the zeros of completesquare x^2+12x-4

The zeros of completesquare x^2+12x-4 are (x+6)^2-40

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complete the square

x^{2} + 12 x - 4

(x + 6)^{2} - 40

Solution steps

x^{2} + 12 x - 4

Write

x^{2} + 12 x - 4

in the form:

x^{2} + 2 a x + a^{2}

2 a = 12 : a = 6

Add and subtract

6^{2}

x^{2} + 12 x - 4 + 6^{2} - 6^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 12 x + 6^{2} = (x + 6)^{2}

(x + 6)^{2} - 4 - 6^{2}

Simplify

(x + 6)^{2} - 40

t, d = - 3 t^{2} + 12 t - 7

x^{2} - 2 x + 7 = 3

x^{2} + 12 x + 4

x^{2} + 4 x - 31 = - 10

5123.1744 = \frac{1}{2} (20.9 + 45.1 + 42.8) x^{2}

What are the solutions to the equation completesquare x^2+12x-4 ?
The solutions to the equation completesquare x^2+12x-4 are (x+6)^2-40
Find the zeros of completesquare x^2+12x-4
The zeros of completesquare x^2+12x-4 are (x+6)^2-40