What are the solutions to the equation completesquare x^2+8x-35=0 ?

The solutions to the equation completesquare x^2+8x-35=0 are x=sqrt(51)-4,x=-sqrt(51)-4

Find the zeros of completesquare x^2+8x-35=0

The zeros of completesquare x^2+8x-35=0 are x=sqrt(51)-4,x=-sqrt(51)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 8 x - 35 = 0

x = 51 - 4, x = - 51 - 4

Decimal Notation

x = 3.14142 \dots, x = - 11.14142 \dots

Solution steps

x^{2} + 8 x - 35 = 0

Move

35

to the right side

x^{2} + 8 x = 35

Rewrite in the form

(x + a)^{2} = b

(x + 4)^{2} = 51

For

the solutions are

f (x) = a, - a

Solve

x + 4 = 51 : x = 51 - 4

Solve

x + 4 = - 51 : x = - 51 - 4

The solutions to the quadratic equation are:

x = 51 - 4, x = - 51 - 4

x^{2} + 15 x + 64 = 0

(x - 5)^{2} = 2

12 x^{2} + 12 x - 72 = 0

40 x - x^{2} = 0

x^{2} + 8 x - 5

What are the solutions to the equation completesquare x^2+8x-35=0 ?
The solutions to the equation completesquare x^2+8x-35=0 are x=sqrt(51)-4,x=-sqrt(51)-4
Find the zeros of completesquare x^2+8x-35=0
The zeros of completesquare x^2+8x-35=0 are x=sqrt(51)-4,x=-sqrt(51)-4