What are the solutions to the equation solvefor r,y=2(x+r)^2-s ?

The solutions to the equation solvefor r,y=2(x+r)^2-s are r=sqrt((y+s)/2)-x,r=-sqrt((y+s)/2)-x

Find the zeros of solvefor r,y=2(x+r)^2-s

The zeros of solvefor r,y=2(x+r)^2-s are r=sqrt((y+s)/2)-x,r=-sqrt((y+s)/2)-x

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solve for

r, y = 2 (x + r)^{2} - s

r = \frac{y + s}{2} - x, r = - \frac{y + s}{2} - x

Solution steps

y = 2 (x + r)^{2} - s

Switch sides

2 (x + r)^{2} - s = y

Move

s

to the right side

2 (x + r)^{2} = y + s

Divide both sides by

2

(x + r)^{2} = \frac{y + s}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + r = \frac{y + s}{2} : r = \frac{y + s}{2} - x

Solve

x + r = - \frac{y + s}{2} : r = - \frac{y + s}{2} - x

The solutions to the quadratic equation are:

r = \frac{y + s}{2} - x, r = - \frac{y + s}{2} - x

2 x^{2} = 5 x + 5

2 x^{2} = 5 x + 7

2 x^{2} = 5 x + 1

3 x^{2} + 10 x = 8

(x + 4)^{2} + (x - 6)^{2} = 82

What are the solutions to the equation solvefor r,y=2(x+r)^2-s ?
The solutions to the equation solvefor r,y=2(x+r)^2-s are r=sqrt((y+s)/2)-x,r=-sqrt((y+s)/2)-x
Find the zeros of solvefor r,y=2(x+r)^2-s
The zeros of solvefor r,y=2(x+r)^2-s are r=sqrt((y+s)/2)-x,r=-sqrt((y+s)/2)-x