What are the solutions to the equation factor x^2+17x+49=3x ?

The solutions to the equation factor x^2+17x+49=3x are x=-7

Find the zeros of factor x^2+17x+49=3x

The zeros of factor x^2+17x+49=3x are x=-7

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x^{2} + 17 x + 49 = 3 x

x = - 7

Solution steps

x^{2} + 17 x + 49 = 3 x

Move

3 x

to the left side

x^{2} + 14 x + 49 = 0

Factor

x^{2} + 14 x + 49 : (x + 7)^{2}

(x + 7)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0

Solve

x + 7 = 0 : x = - 7

The solution to the quadratic equation is:

x = - 7

6 x^{2} - 600 = 0

12 x^{2} - 19 x + 4 = 0

(4.5 - 1.5 x) (\frac{3 - x}{2}) - (3.25 - 1.5 x) (3 - x) - m = 0

a^{2} - 3 = 0

k^{2} - 6 = - 50

What are the solutions to the equation factor x^2+17x+49=3x ?
The solutions to the equation factor x^2+17x+49=3x are x=-7
Find the zeros of factor x^2+17x+49=3x
The zeros of factor x^2+17x+49=3x are x=-7