What are the solutions to the equation 15x^2-17x+4=0 ?

The solutions to the equation 15x^2-17x+4=0 are x= 4/5 ,x= 1/3

Find the zeros of 15x^2-17x+4=0

The zeros of 15x^2-17x+4=0 are x= 4/5 ,x= 1/3

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15 x^{2} - 17 x + 4 = 0

x = \frac{4}{5}, x = \frac{1}{3}

Decimal Notation

x = 0.8, x = 0.33333 \dots

Solution steps

15 x^{2} - 17 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 15 \cdot 4}{2 \cdot 15}

(- 17)^{2} - 4 \cdot 15 \cdot 4 = 7

x_{1, 2} = \frac{- ( - 17 ) \pm 7}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 7}{2 \cdot 15}, x_{2} = \frac{- ( - 17 ) - 7}{2 \cdot 15}

x = \frac{- ( - 17 ) + 7}{2 \cdot 15} : \frac{4}{5}

x = \frac{- ( - 17 ) - 7}{2 \cdot 15} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = \frac{1}{3}

9 = \frac{8}{5} (x + 5) 58 (x + 5)

- 5 x^{2} - 6 x - 1 = 0

0 = - 4.9 t^{2} + 28 t

12 x^{2} + 42 x - 294 = 0

x^{2} - x - 1 = 6 x - 1

What are the solutions to the equation 15x^2-17x+4=0 ?
The solutions to the equation 15x^2-17x+4=0 are x= 4/5 ,x= 1/3
Find the zeros of 15x^2-17x+4=0
The zeros of 15x^2-17x+4=0 are x= 4/5 ,x= 1/3