What are the solutions to the equation 4x^2+8x=-2 ?

The solutions to the equation 4x^2+8x=-2 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))

Find the zeros of 4x^2+8x=-2

The zeros of 4x^2+8x=-2 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))

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4 x^{2} + 8 x = - 2

x = \frac{- 2 + 2}{2}, x = - \frac{2 + 1}{2}

Decimal Notation

x = - 0.29289 \dots, x = - 1.70710 \dots

Solution steps

4 x^{2} + 8 x = - 2

Move

2

to the left side

4 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 2 = 42

x_{1, 2} = \frac{- 8 \pm 4 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 2}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 2}{2 \cdot 4}

x = \frac{- 8 + 4 2}{2 \cdot 4} : \frac{- 2 + 2}{2}

x = \frac{- 8 - 4 2}{2 \cdot 4} : - \frac{2 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 2}{2}, x = - \frac{2 + 1}{2}

- x^{2} + 2 x + 3 = 0

4 y^{2} = 0

2 x^{2} - 3 x = - 8

3 (x^{2} - 1) = 9

12 x^{2} + 2 = - 2

What are the solutions to the equation 4x^2+8x=-2 ?
The solutions to the equation 4x^2+8x=-2 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))
Find the zeros of 4x^2+8x=-2
The zeros of 4x^2+8x=-2 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))