What are the solutions to the equation x^2-12x-35=0 ?

The solutions to the equation x^2-12x-35=0 are x=6+sqrt(71),x=6-sqrt(71)

Find the zeros of x^2-12x-35=0

The zeros of x^2-12x-35=0 are x=6+sqrt(71),x=6-sqrt(71)

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x^{2} - 12 x - 35 = 0

x = 6 + 71, x = 6 - 71

Decimal Notation

x = 14.42614 \dots, x = - 2.42614 \dots

Solution steps

x^{2} - 12 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 35) = 271

x_{1, 2} = \frac{- ( - 12 ) \pm 2 71}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 71}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 71}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 71}{2 \cdot 1} : 6 + 71

x = \frac{- ( - 12 ) - 2 71}{2 \cdot 1} : 6 - 71

The solutions to the quadratic equation are:

x = 6 + 71, x = 6 - 71

x^{2} - 2 x = 17

x, x^{2} + 4 y^{2} + 4 x - 24 y + 24 y + 24 = 0

5 x^{2} + 5 x = 5

x^{2} - 48 x = 0

(2 x + 3) (2 x - 3) = 135

What are the solutions to the equation x^2-12x-35=0 ?
The solutions to the equation x^2-12x-35=0 are x=6+sqrt(71),x=6-sqrt(71)
Find the zeros of x^2-12x-35=0
The zeros of x^2-12x-35=0 are x=6+sqrt(71),x=6-sqrt(71)