en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^2-p-12=0

Solution

p^{2} - p - 12 = 0

Solution

p = 4, p = - 3

Solution steps

p^{2} - p - 12 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

p_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, p_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

p = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

p = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

p = 4, p = - 3

Popular Examples

10 n^{2} - n - 8 = 0

solvefor s,f={(1-2s^2)/(-x+2)}solve for

s, f = {\frac{1 - 2 s ^{2}}{- x + 2}}

x^{2} - 40 x - 800 = 0

completesquare 6x^2+120x+2070=0 complete the square

6 x^{2} + 120 x + 2070 = 0

solvefor x,x^2+2xy+y^2+2x-4y+5=0 solve for

x, x^{2} + 2 x y + y^{2} + 2 x - 4 y + 5 = 0

Frequently Asked Questions (FAQ)

What are the solutions to the equation p^2-p-12=0 ?
The solutions to the equation p^2-p-12=0 are p=4,p=-3
Find the zeros of p^2-p-12=0
The zeros of p^2-p-12=0 are p=4,p=-3