What are the solutions to the equation -x^2+8x=-15 ?

The solutions to the equation -x^2+8x=-15 are x=4-sqrt(31),x=4+sqrt(31)

Find the zeros of -x^2+8x=-15

The zeros of -x^2+8x=-15 are x=4-sqrt(31),x=4+sqrt(31)

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- x^{2} + 8 x = - 15

x = 4 - 31, x = 4 + 31

Decimal Notation

x = - 1.56776 \dots, x = 9.56776 \dots

Solution steps

- x^{2} + 8 x = - 15

Move

15

to the left side

- x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 15}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 15 = 231

x_{1, 2} = \frac{- 8 \pm 2 31}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 31}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 31}{2 ( - 1 )}

x = \frac{- 8 + 2 31}{2 ( - 1 )} : 4 - 31

x = \frac{- 8 - 2 31}{2 ( - 1 )} : 4 + 31

The solutions to the quadratic equation are:

x = 4 - 31, x = 4 + 31

1 + 2 + 2^{2} + 2 n - 1 = n^{2}

x, x^{2} - 9 x + 20 = 0

- 3 x^{2} = x

(x - 14)^{2} + 13 = 14

x (x + 9) = 1

What are the solutions to the equation -x^2+8x=-15 ?
The solutions to the equation -x^2+8x=-15 are x=4-sqrt(31),x=4+sqrt(31)
Find the zeros of -x^2+8x=-15
The zeros of -x^2+8x=-15 are x=4-sqrt(31),x=4+sqrt(31)