What are the solutions to the equation -9n^2+2n+21=-5n^2 ?

The solutions to the equation -9n^2+2n+21=-5n^2 are n=-(-1+sqrt(85))/4 ,n=(1+sqrt(85))/4

Find the zeros of -9n^2+2n+21=-5n^2

The zeros of -9n^2+2n+21=-5n^2 are n=-(-1+sqrt(85))/4 ,n=(1+sqrt(85))/4

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- 9 n^{2} + 2 n + 21 = - 5 n^{2}

n = - \frac{- 1 + 85}{4}, n = \frac{1 + 85}{4}

Decimal Notation

n = - 2.05488 \dots, n = 2.55488 \dots

Solution steps

- 9 n^{2} + 2 n + 21 = - 5 n^{2}

Move

5 n^{2}

to the left side

- 4 n^{2} + 2 n + 21 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 4 ) \cdot 21}{2 ( - 4 )}

2^{2} - 4 (- 4) \cdot 21 = 285

n_{1, 2} = \frac{- 2 \pm 2 85}{2 ( - 4 )}

Separate the solutions

n_{1} = \frac{- 2 + 2 85}{2 ( - 4 )}, n_{2} = \frac{- 2 - 2 85}{2 ( - 4 )}

n = \frac{- 2 + 2 85}{2 ( - 4 )} : - \frac{- 1 + 85}{4}

n = \frac{- 2 - 2 85}{2 ( - 4 )} : \frac{1 + 85}{4}

The solutions to the quadratic equation are:

n = - \frac{- 1 + 85}{4}, n = \frac{1 + 85}{4}

4 x^{2} + 6 x = 0

- 8 + x^{2} = 0

x^{2} + 4 x - 8 = 0

6 x^{2} = 42

6 x^{2} = 6 x

What are the solutions to the equation -9n^2+2n+21=-5n^2 ?
The solutions to the equation -9n^2+2n+21=-5n^2 are n=-(-1+sqrt(85))/4 ,n=(1+sqrt(85))/4
Find the zeros of -9n^2+2n+21=-5n^2
The zeros of -9n^2+2n+21=-5n^2 are n=-(-1+sqrt(85))/4 ,n=(1+sqrt(85))/4