What are the solutions to the equation -0.5x^2+40x-300=300 ?

The solutions to the equation -0.5x^2+40x-300=300 are x=20,x=60

Find the zeros of -0.5x^2+40x-300=300

The zeros of -0.5x^2+40x-300=300 are x=20,x=60

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- 0.5 x^{2} + 40 x - 300 = 300

x = 20, x = 60

Solution steps

- 0.5 x^{2} + 40 x - 300 = 300

Multiply both sides by

10

- 5 x^{2} + 400 x - 3000 = 3000

Move

3000

to the left side

- 5 x^{2} + 400 x - 6000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 5 ) ( - 6000 )}{2 ( - 5 )}

40 0^{2} - 4 (- 5) (- 6000) = 200

x_{1, 2} = \frac{- 400 \pm 200}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 400 + 200}{2 ( - 5 )}, x_{2} = \frac{- 400 - 200}{2 ( - 5 )}

x = \frac{- 400 + 200}{2 ( - 5 )} : 20

x = \frac{- 400 - 200}{2 ( - 5 )} : 60

The solutions to the quadratic equation are:

x = 20, x = 60

3 x^{2} + 12 x = 15

88 = \frac{( x + 5 ) ( x )}{2}

\frac{x ^{2}}{2} - x = 1

X^{2} - \frac{7}{6} X + \frac{1}{3} = 0

6 w^{2} - 11 w + 5 = 0

What are the solutions to the equation -0.5x^2+40x-300=300 ?
The solutions to the equation -0.5x^2+40x-300=300 are x=20,x=60
Find the zeros of -0.5x^2+40x-300=300
The zeros of -0.5x^2+40x-300=300 are x=20,x=60