What are the solutions to the equation 2x^2+9x=x-368 ?

The solutions to the equation 2x^2+9x=x-368 are x=-2+6sqrt(5)i,x=-2-6sqrt(5)i

Find the zeros of 2x^2+9x=x-368

The zeros of 2x^2+9x=x-368 are x=-2+6sqrt(5)i,x=-2-6sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 9 x = x - 368

x = - 2 + 65 i, x = - 2 - 65 i

Solution steps

2 x^{2} + 9 x = x - 368

Move

368

to the left side

2 x^{2} + 9 x + 368 = x

Move

x

to the left side

2 x^{2} + 8 x + 368 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 368}{2 \cdot 2}

Simplify

8^{2} - 4 \cdot 2 \cdot 368 : 245 i

x_{1, 2} = \frac{- 8 \pm 24 5 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 24 5 i}{2 \cdot 2}, x_{2} = \frac{- 8 - 24 5 i}{2 \cdot 2}

x = \frac{- 8 + 24 5 i}{2 \cdot 2} : - 2 + 65 i

x = \frac{- 8 - 24 5 i}{2 \cdot 2} : - 2 - 65 i

The solutions to the quadratic equation are:

x = - 2 + 65 i, x = - 2 - 65 i

x^{2} = 8 0^{2} + 6 0^{2}

x^{2} - x = x - 5

x - 4 = \frac{( x - 22 ) ^{2}}{3}

12 x^{2} + 16 = 0

x^{2} - 24 x - 82 = 0

What are the solutions to the equation 2x^2+9x=x-368 ?
The solutions to the equation 2x^2+9x=x-368 are x=-2+6sqrt(5)i,x=-2-6sqrt(5)i
Find the zeros of 2x^2+9x=x-368
The zeros of 2x^2+9x=x-368 are x=-2+6sqrt(5)i,x=-2-6sqrt(5)i