What are the solutions to the equation b^2-9b+8=0 ?

The solutions to the equation b^2-9b+8=0 are b=8,b=1

Find the zeros of b^2-9b+8=0

The zeros of b^2-9b+8=0 are b=8,b=1

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b^{2} - 9 b + 8 = 0

b = 8, b = 1

Solution steps

b^{2} - 9 b + 8 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

b_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, b_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

b = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

b = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

b = 8, b = 1

5 + \frac{5}{8} + \frac{5}{8} + \frac{5}{8} + \frac{5}{8} - 0.625

x^{2} + 11 x + 28

2 a^{2} - 3 a + 1

- 2 (\frac{2}{5})^{- 1}

2 x^{2} + 5 x - 12 = 0

What are the solutions to the equation b^2-9b+8=0 ?
The solutions to the equation b^2-9b+8=0 are b=8,b=1
Find the zeros of b^2-9b+8=0
The zeros of b^2-9b+8=0 are b=8,b=1