What are the solutions to the equation x^2-4x=-12 ?

The solutions to the equation x^2-4x=-12 are x=2+2sqrt(2)i,x=2-2sqrt(2)i

Find the zeros of x^2-4x=-12

The zeros of x^2-4x=-12 are x=2+2sqrt(2)i,x=2-2sqrt(2)i

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x^{2} - 4 x = - 12

x = 2 + 22 i, x = 2 - 22 i

Solution steps

x^{2} - 4 x = - 12

Move

12

to the left side

x^{2} - 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 12 : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 1} : 2 + 22 i

x = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 1} : 2 - 22 i

The solutions to the quadratic equation are:

x = 2 + 22 i, x = 2 - 22 i

x^{2} + 3.9 x + 1.8 = 0

a x^{2} + b x + 1 = 0

2.4 z^{2} - 7.4 z - 2.4 = 0

2 x^{2} + 4 x - 3 = 0

x^{2} + 4 x + 4 = - 25

What are the solutions to the equation x^2-4x=-12 ?
The solutions to the equation x^2-4x=-12 are x=2+2sqrt(2)i,x=2-2sqrt(2)i
Find the zeros of x^2-4x=-12
The zeros of x^2-4x=-12 are x=2+2sqrt(2)i,x=2-2sqrt(2)i