What are the solutions to the equation 0=(-2x+3)(-x+3) ?

The solutions to the equation 0=(-2x+3)(-x+3) are x= 3/2 ,x=3

Find the zeros of 0=(-2x+3)(-x+3)

The zeros of 0=(-2x+3)(-x+3) are x= 3/2 ,x=3

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0 = (- 2 x + 3) (- x + 3)

x = \frac{3}{2}, x = 3

Decimal Notation

x = 1.5, x = 3

Solution steps

0 = (- 2 x + 3) (- x + 3)

Switch sides

(- 2 x + 3) (- x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 2 x + 3 = 0 or - x + 3 = 0

Solve

- 2 x + 3 = 0 : x = \frac{3}{2}

Solve

- x + 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 3

9 X^{2} - 81 = 0

- 6 x^{2} + 6 x + 3 = 4 + 4 x

x^{2} = - 3 x - 3 x

- 4 x^{2} - 7 x + 3 = 0

x^{2} + 40 x - 3199998585 = 0

What are the solutions to the equation 0=(-2x+3)(-x+3) ?
The solutions to the equation 0=(-2x+3)(-x+3) are x= 3/2 ,x=3
Find the zeros of 0=(-2x+3)(-x+3)
The zeros of 0=(-2x+3)(-x+3) are x= 3/2 ,x=3