What are the solutions to the equation 0=x^2-6x-5 ?

The solutions to the equation 0=x^2-6x-5 are x=3+sqrt(14),x=3-sqrt(14)

Find the zeros of 0=x^2-6x-5

The zeros of 0=x^2-6x-5 are x=3+sqrt(14),x=3-sqrt(14)

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0 = x^{2} - 6 x - 5

x = 3 + 14, x = 3 - 14

Decimal Notation

x = 6.74165 \dots, x = - 0.74165 \dots

Solution steps

0 = x^{2} - 6 x - 5

Switch sides

x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 5) = 214

x_{1, 2} = \frac{- ( - 6 ) \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 14}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 14}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 14}{2 \cdot 1} : 3 + 14

x = \frac{- ( - 6 ) - 2 14}{2 \cdot 1} : 3 - 14

The solutions to the quadratic equation are:

x = 3 + 14, x = 3 - 14

4 z^{2} - 3 z - 3 = 0

0 = x^{2} - 12 x + 27

x^{2} - 4 x - 480 = 0

10 x^{2} - 9 = 0

3 0^{2} + 4 5^{2} = x^{2}

What are the solutions to the equation 0=x^2-6x-5 ?
The solutions to the equation 0=x^2-6x-5 are x=3+sqrt(14),x=3-sqrt(14)
Find the zeros of 0=x^2-6x-5
The zeros of 0=x^2-6x-5 are x=3+sqrt(14),x=3-sqrt(14)