What are the solutions to the equation 0=6x^2+x-5 ?

The solutions to the equation 0=6x^2+x-5 are x= 5/6 ,x=-1

Find the zeros of 0=6x^2+x-5

The zeros of 0=6x^2+x-5 are x= 5/6 ,x=-1

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0 = 6 x^{2} + x - 5

x = \frac{5}{6}, x = - 1

Decimal Notation

x = 0.83333 \dots, x = - 1

Solution steps

0 = 6 x^{2} + x - 5

Switch sides

6 x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 5) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 6}, x_{2} = \frac{- 1 - 11}{2 \cdot 6}

x = \frac{- 1 + 11}{2 \cdot 6} : \frac{5}{6}

x = \frac{- 1 - 11}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - 1

128 = 96 t - 16 t^{2}

(2 k + 3)^{2} - 19 = 81

100 + x^{2} = 220 + 2 x

x^{2} - 6 x + 9 = 0

12 x^{2} - 40 x + 25 = 0

What are the solutions to the equation 0=6x^2+x-5 ?
The solutions to the equation 0=6x^2+x-5 are x= 5/6 ,x=-1
Find the zeros of 0=6x^2+x-5
The zeros of 0=6x^2+x-5 are x= 5/6 ,x=-1