What are the solutions to the equation 6x^2-5x+7=0 ?

The solutions to the equation 6x^2-5x+7=0 are x= 5/12+i(sqrt(143))/(12),x= 5/12-i(sqrt(143))/(12)

Find the zeros of 6x^2-5x+7=0

The zeros of 6x^2-5x+7=0 are x= 5/12+i(sqrt(143))/(12),x= 5/12-i(sqrt(143))/(12)

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6 x^{2} - 5 x + 7 = 0

x = \frac{5}{12} + i \frac{143}{12}, x = \frac{5}{12} - i \frac{143}{12}

Solution steps

6 x^{2} - 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

Simplify

(- 5)^{2} - 4 \cdot 6 \cdot 7 : 143 i

x_{1, 2} = \frac{- ( - 5 ) \pm 143 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 143 i}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 143 i}{2 \cdot 6}

x = \frac{- ( - 5 ) + 143 i}{2 \cdot 6} : \frac{5}{12} + i \frac{143}{12}

x = \frac{- ( - 5 ) - 143 i}{2 \cdot 6} : \frac{5}{12} - i \frac{143}{12}

The solutions to the quadratic equation are:

x = \frac{5}{12} + i \frac{143}{12}, x = \frac{5}{12} - i \frac{143}{12}

x, 3 x^{2} - 2 x - 1 = 0

λ^{2} - λ + 1 = 0

12 x^{2} - 60 x + 5

3 y^{2} + 0.685 y - 2.12 = 0

- 3 x^{2} + 7 x + 4 = 0

What are the solutions to the equation 6x^2-5x+7=0 ?
The solutions to the equation 6x^2-5x+7=0 are x= 5/12+i(sqrt(143))/(12),x= 5/12-i(sqrt(143))/(12)
Find the zeros of 6x^2-5x+7=0
The zeros of 6x^2-5x+7=0 are x= 5/12+i(sqrt(143))/(12),x= 5/12-i(sqrt(143))/(12)