What are the solutions to the equation 750x^2-1350x+210=0 ?

The solutions to the equation 750x^2-1350x+210=0 are x=(9+sqrt(53))/(10),x=(9-sqrt(53))/(10)

Find the zeros of 750x^2-1350x+210=0

The zeros of 750x^2-1350x+210=0 are x=(9+sqrt(53))/(10),x=(9-sqrt(53))/(10)

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750 x^{2} - 1350 x + 210 = 0

x = \frac{9 + 53}{10}, x = \frac{9 - 53}{10}

Decimal Notation

x = 1.62801 \dots, x = 0.17198 \dots

Solution steps

750 x^{2} - 1350 x + 210 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1350 ) \pm ( - 1350 ) ^{2} - 4 \cdot 750 \cdot 210}{2 \cdot 750}

(- 1350)^{2} - 4 \cdot 750 \cdot 210 = 15053

x_{1, 2} = \frac{- ( - 1350 ) \pm 150 53}{2 \cdot 750}

Separate the solutions

x_{1} = \frac{- ( - 1350 ) + 150 53}{2 \cdot 750}, x_{2} = \frac{- ( - 1350 ) - 150 53}{2 \cdot 750}

x = \frac{- ( - 1350 ) + 150 53}{2 \cdot 750} : \frac{9 + 53}{10}

x = \frac{- ( - 1350 ) - 150 53}{2 \cdot 750} : \frac{9 - 53}{10}

The solutions to the quadratic equation are:

x = \frac{9 + 53}{10}, x = \frac{9 - 53}{10}

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What are the solutions to the equation 750x^2-1350x+210=0 ?
The solutions to the equation 750x^2-1350x+210=0 are x=(9+sqrt(53))/(10),x=(9-sqrt(53))/(10)
Find the zeros of 750x^2-1350x+210=0
The zeros of 750x^2-1350x+210=0 are x=(9+sqrt(53))/(10),x=(9-sqrt(53))/(10)