What are the solutions to the equation -5x^2+40x-76=4 ?

The solutions to the equation -5x^2+40x-76=4 are x=4

Find the zeros of -5x^2+40x-76=4

The zeros of -5x^2+40x-76=4 are x=4

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- 5 x^{2} + 40 x - 76 = 4

x = 4

Solution steps

- 5 x^{2} + 40 x - 76 = 4

Move

4

to the left side

- 5 x^{2} + 40 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 5 ) ( - 80 )}{2 ( - 5 )}

4 0^{2} - 4 (- 5) (- 80) = 0

x_{1, 2} = \frac{- 40 \pm 0}{2 ( - 5 )}

x = \frac{- 40}{2 ( - 5 )}

\frac{- 40}{2 ( - 5 )} = 4

x = 4

The solution to the quadratic equation is:

x = 4

2 x^{2} + 4 x - 576 = 0

3 x^{2} - 2 = 6 x

3 x^{2} - 2 = 58

3 x^{2} - 2 = 2 x

7 x^{2} - 3 x

What are the solutions to the equation -5x^2+40x-76=4 ?
The solutions to the equation -5x^2+40x-76=4 are x=4
Find the zeros of -5x^2+40x-76=4
The zeros of -5x^2+40x-76=4 are x=4