What are the solutions to the equation y^2-15y+14=-5y ?

The solutions to the equation y^2-15y+14=-5y are y=5+sqrt(11),y=5-sqrt(11)

Find the zeros of y^2-15y+14=-5y

The zeros of y^2-15y+14=-5y are y=5+sqrt(11),y=5-sqrt(11)

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y^{2} - 15 y + 14 = - 5 y

y = 5 + 11, y = 5 - 11

Decimal Notation

y = 8.31662 \dots, y = 1.68337 \dots

Solution steps

y^{2} - 15 y + 14 = - 5 y

Move

5 y

to the left side

y^{2} - 10 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 14 = 211

y_{1, 2} = \frac{- ( - 10 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 11}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 11}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 11}{2 \cdot 1} : 5 + 11

y = \frac{- ( - 10 ) - 2 11}{2 \cdot 1} : 5 - 11

The solutions to the quadratic equation are:

y = 5 + 11, y = 5 - 11

x^{2} + 2 x + 2 = 0

x^{2} - 3 x = x - 4 x^{2}

x^{2} + \frac{4}{5} x

k r^{2} + (2 k + 6) r + 16 = 0

6 + 5 x = 6 x^{2}

What are the solutions to the equation y^2-15y+14=-5y ?
The solutions to the equation y^2-15y+14=-5y are y=5+sqrt(11),y=5-sqrt(11)
Find the zeros of y^2-15y+14=-5y
The zeros of y^2-15y+14=-5y are y=5+sqrt(11),y=5-sqrt(11)