What are the solutions to the equation -2x^2-7=0 ?

The solutions to the equation -2x^2-7=0 are x=sqrt(7/2)i,x=-sqrt(7/2)i

Find the zeros of -2x^2-7=0

The zeros of -2x^2-7=0 are x=sqrt(7/2)i,x=-sqrt(7/2)i

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- 2 x^{2} - 7 = 0

x = \frac{7}{2} i, x = - \frac{7}{2} i

Solution steps

- 2 x^{2} - 7 = 0

Move

7

to the right side

- 2 x^{2} = 7

Divide both sides by

- 2

x^{2} = - \frac{7}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{7}{2}, x = - - \frac{7}{2}

- \frac{7}{2} = \frac{7}{2} i

- - \frac{7}{2} = - \frac{7}{2} i

x = \frac{7}{2} i, x = - \frac{7}{2} i

x^{2} - 3 x - 57 = 0

g (r) = - (r + 11) (r + 14)

x^{2} + 5 x + 6 = 2

49 x^{2} + 42 x + 9 = 0

1 5^{2} + 1 5^{2} = x^{2}

What are the solutions to the equation -2x^2-7=0 ?
The solutions to the equation -2x^2-7=0 are x=sqrt(7/2)i,x=-sqrt(7/2)i
Find the zeros of -2x^2-7=0
The zeros of -2x^2-7=0 are x=sqrt(7/2)i,x=-sqrt(7/2)i