What are the solutions to the equation quadraticformula x^2+2x+4=0 ?

The solutions to the equation quadraticformula x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of quadraticformula x^2+2x+4=0

The zeros of quadraticformula x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

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x^{2} + 2 x + 4 = 0

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

x = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

x, (x - 1)^{2} + (y - 2)^{2} = 0

A = x^{2} + 6 x + 5

4 (x + 3)^{2} + 9 = - 29

B, A = (A - B) \cup B

r^{2} = 2 \frac{1}{2}

What are the solutions to the equation quadraticformula x^2+2x+4=0 ?
The solutions to the equation quadraticformula x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of quadraticformula x^2+2x+4=0
The zeros of quadraticformula x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i