What are the solutions to the equation 2(x+5)^2=12 ?

The solutions to the equation 2(x+5)^2=12 are x=sqrt(6)-5,x=-sqrt(6)-5

Find the zeros of 2(x+5)^2=12

The zeros of 2(x+5)^2=12 are x=sqrt(6)-5,x=-sqrt(6)-5

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2 (x + 5)^{2} = 12

x = 6 - 5, x = - 6 - 5

Decimal Notation

x = - 2.55051 \dots, x = - 7.44948 \dots

Solution steps

2 (x + 5)^{2} = 12

Divide both sides by

2

(x + 5)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 6 : x = 6 - 5

Solve

x + 5 = - 6 : x = - 6 - 5

The solutions to the quadratic equation are:

x = 6 - 5, x = - 6 - 5

x^{2} - 4 x - 13

x^{2} - 9 x + x = 0

x^{2} - 4 x + 29

k^{2} - 2 k + 2 = 0

(12 x^{2} + 2 x - 2) = 0

What are the solutions to the equation 2(x+5)^2=12 ?
The solutions to the equation 2(x+5)^2=12 are x=sqrt(6)-5,x=-sqrt(6)-5
Find the zeros of 2(x+5)^2=12
The zeros of 2(x+5)^2=12 are x=sqrt(6)-5,x=-sqrt(6)-5