What are the solutions to the equation 2k^2+3k-13=k^2+15 ?

The solutions to the equation 2k^2+3k-13=k^2+15 are k=4,k=-7

Find the zeros of 2k^2+3k-13=k^2+15

The zeros of 2k^2+3k-13=k^2+15 are k=4,k=-7

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2 k^{2} + 3 k - 13 = k^{2} + 15

k = 4, k = - 7

Solution steps

2 k^{2} + 3 k - 13 = k^{2} + 15

Move

15

to the left side

2 k^{2} + 3 k - 28 = k^{2}

Move

k^{2}

to the left side

k^{2} + 3 k - 28 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

k_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 3 + 11}{2 \cdot 1}, k_{2} = \frac{- 3 - 11}{2 \cdot 1}

k = \frac{- 3 + 11}{2 \cdot 1} : 4

k = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

k = 4, k = - 7

\frac{14}{15} - \frac{2}{3} x^{2} = - \frac{127}{30}

x^{2} - 2 x + 4 = 0

x^{2} - 30 x + 250

3^{2} + 9^{2} = c^{2}

4 = (x - 1)^{2}

What are the solutions to the equation 2k^2+3k-13=k^2+15 ?
The solutions to the equation 2k^2+3k-13=k^2+15 are k=4,k=-7
Find the zeros of 2k^2+3k-13=k^2+15
The zeros of 2k^2+3k-13=k^2+15 are k=4,k=-7