What are the solutions to the equation x(1+x)-1/2 (x-2)-1/2 x-1=9 ?

The solutions to the equation x(1+x)-1/2 (x-2)-1/2 x-1=9 are x=3,x=-3

Find the zeros of x(1+x)-1/2 (x-2)-1/2 x-1=9

The zeros of x(1+x)-1/2 (x-2)-1/2 x-1=9 are x=3,x=-3

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x (1 + x) - \frac{1}{2} (x - 2) - \frac{1}{2} x - 1 = 9

x = 3, x = - 3

Solution steps

x (1 + x) - \frac{1}{2} (x - 2) - \frac{1}{2} x - 1 = 9

Multiply both sides by

2

2 x (1 + x) - (x - 2) - x - 2 = 18

Expand

2 x (1 + x) - (x - 2) - x - 2 : 2 x^{2}

2 x^{2} = 18

Move

18

to the left side

2 x^{2} - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 18) = 12

x_{1, 2} = \frac{- 0 \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 12}{2 \cdot 2}, x_{2} = \frac{- 0 - 12}{2 \cdot 2}

x = \frac{- 0 + 12}{2 \cdot 2} : 3

x = \frac{- 0 - 12}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 3, x = - 3

x^{2} - 42 = 0

3 y^{2} + 24 y + 36 = 0

3 x^{2} - 16 - 12 = 0

u^{2} + 7 u + 12 = 0

12 x^{2} - 14 x - 10 = 0

What are the solutions to the equation x(1+x)-1/2 (x-2)-1/2 x-1=9 ?
The solutions to the equation x(1+x)-1/2 (x-2)-1/2 x-1=9 are x=3,x=-3
Find the zeros of x(1+x)-1/2 (x-2)-1/2 x-1=9
The zeros of x(1+x)-1/2 (x-2)-1/2 x-1=9 are x=3,x=-3